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Problem 10 (Problem 79 in Textbook)A 32.0 kg wheel, essentially a thin hoop with radius 1.20 m, is rotating at 280 rev/min. It must be brought to a stop in 15.0 s. (a) How much work must be done to stop it? Solution: First, we have to find the rotational inertia of the body. Then plugging the rotational inertia equation from Table 11-2 into the rotational kinetic energy equation, we obtain the following setup.
(b) What is the required power? Solution: Using the power equation, we obtain the following setup.
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